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Taxi fare from 5 Senkow Dr to Boston - Logan International Airport



Remember that below taxi fares are based on estimated Taxi Rates in Waterford, CT. How much you'll be actually charged for your ride between 5 Senkow Dr and Boston - Logan International Airport may vary due to the time of the day, tolls, road & weather conditions, inaccuracy of collected pricing data, etc.

This taxi fare from 5 Senkow Dr (5 Senkow Dr, Quaker Hill, CT 06375, USA) to Boston - Logan International Airport (Boston, MA 02128, USA) was estimated 2417 days ago.
Re-estimate to see the most up-to-date info.


Average fares by taxi class


STANDARD

Toyota Camry and similar.

Approx. examples:
Uber X,
Lyft.

▽ Fare Breakdown

Initial Fee: 4.90 $
Cost of travel time: 38.40 $
Cost of distance : 114.02 $

Total taxi fare
estimated average:
~ 157.32 $


XL

Van, SUV and similar.

Approx. examples:
Uber XL,
Lyft XL.

▽ Fare Breakdown

Initial Fee: 6.80 $
Cost of travel time: 51.20 $
Cost of distance : 239.44 $

Total taxi fare
estimated average:
~ 297.44 $

Distance & time

▽ Click to show route

Taxis from 5 Senkow Dr to Boston - Logan International Airport

To get from 5 Senkow Dr to Boston - Logan International Airport, the following taxis are available:

    UBER  website  

Uber fares below are the same as you would see via the Uber app.


uberX
235-310 $ (Up 70%)
~8 min away  


PREMIUM
343-454 $
~17 min away  


uberXL
403-533 $ (Up 70%)
~17 min away  


PREMIUM SUV
444-588 $
~17 min away  

    LYFT  website  

Lyft fares below are the same as you would see via the Lyft app.


Lyft
142-143 $
~9 min away  


Lyft Plus
245-246 $
~0 min away  


Lyft Premier
354-355 $
~9 min away  

Q & A

Travel time from 5 Senkow Dr to Boston - Logan International Airport?

Travel time by taxi is approximately 128 min to get from 5 Senkow Dr to Boston - Logan International Airport.

Distance between 5 Senkow Dr and Boston - Logan International Airport?

The road distance between 5 Senkow Dr and Boston - Logan International Airport is 114.02 miles (183.5 km).

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