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Taxi fare from Lexington Avenue to 1012 Bentbrook Pl



Remember that below taxi fares are based on estimated Taxi Rates in Norman, OK. How much you'll be actually charged for your ride between Lexington Avenue and 1012 Bentbrook Pl may vary due to the time of the day, tolls, road & weather conditions, inaccuracy of collected pricing data, etc.

This taxi fare from Lexington Avenue (Lexington Ave, Norman, OK 73069, USA) to 1012 Bentbrook Pl (1012 Bentbrook Pl, Norman, OK 73072, USA) was estimated 2089 days ago.
Re-estimate to see the most up-to-date info.


Average fares by taxi class


STANDARD

Toyota Camry and similar.

Approx. examples:
Uber X,
Lyft.

▽ Fare Breakdown

Initial Fee: 4.00 $
Cost of travel time: 1.00 $
Cost of distance : 3.13 $

Total taxi fare
estimated average:
~ 8.13 $


XL

Van, SUV and similar.

Approx. examples:
Uber XL,
Lyft XL.

▽ Fare Breakdown

Initial Fee: 5.00 $
Cost of travel time: 3.00 $
Cost of distance : 5.92 $

Total taxi fare
estimated average:
~ 13.92 $


COMFORT

Audi A6 and similar.

Approx. examples:
Uber Select,
Lyft Plus.

▽ Fare Breakdown

Initial Fee: 9.00 $
Cost of travel time: 4.00 $
Cost of distance : 9.05 $

Total taxi fare
estimated average:
~ 22.05 $

Distance & time

▽ Click to show route

Taxis from Lexington Avenue to 1012 Bentbrook Pl

To get from Lexington Avenue to 1012 Bentbrook Pl, the following taxis are available:

    UBER  website  

Uber fares below are the same as you would see via the Uber app.


UberX
6-9 $
~12 min away  


UberXL
11-14 $
~13 min away  


Select
18-22 $
~13 min away  

    LYFT  website  

Lyft fares below are the same as you would see via the Lyft app.


Lyft
6-8 $
~6 min away  


Lyft XL
12-15 $
~15 min away  


Lux
18-21 $
~15 min away  

Q & A

Travel time from Lexington Avenue to 1012 Bentbrook Pl?

Travel time by taxi is approximately 10 min to get from Lexington Avenue to 1012 Bentbrook Pl.

Distance between Lexington Avenue and 1012 Bentbrook Pl?

The road distance between Lexington Avenue and 1012 Bentbrook Pl is 3.48 miles (5.6 km).

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