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Taxi fare from 2 Victoria Ct to Newark



Remember that below taxi fares are based on estimated Taxi Rates in Cranford, NJ. How much you'll be actually charged for your ride between 2 Victoria Ct and Newark may vary due to the time of the day, tolls, road & weather conditions, inaccuracy of collected pricing data, etc.

This taxi fare from 2 Victoria Ct (2 Victoria St, San Francisco, CA 94132, USA) to Newark (Newark, NJ, USA) was estimated 2531 days ago.
Re-estimate to see the most up-to-date info.


Average fares by taxi class


STANDARD

Toyota Camry and similar.

Approx. examples:
Uber X,
Lyft.

▽ Fare Breakdown

Initial Fee: 4.20 $
Cost of travel time: 7.20 $
Cost of distance : 15.26 $

Total taxi fare
estimated average:
~ 26.66 $


XL

Van, SUV and similar.

Approx. examples:
Uber XL,
Lyft XL.

▽ Fare Breakdown

Initial Fee: 5.00 $
Cost of travel time: 7.20 $
Cost of distance : 25.44 $

Total taxi fare
estimated average:
~ 37.64 $


BUSINESS

Mersedes E-class and similar.

Approx. examples:
Uber Black,
Lyft Lux Black.

▽ Fare Breakdown

Initial Fee: 8.50 $
Cost of travel time: 28.80 $
Cost of distance : 58.51 $

Total taxi fare
estimated average:
~ 95.81 $

Distance & time

▽ Click to show route

Taxis from 2 Victoria Ct to Newark

To get from 2 Victoria Ct to Newark, the following taxis are available:

    UBER  website  

Uber fares below are the same as you would see via the Uber app.


uberX
19-25 $
~4 min away  


uberPOOL
20-26 $
~4 min away  


uberXL
28-37 $
~22 min away  


uberBLACK
72-94 $
~11 min away  


UberSUV
92-119 $
~11 min away  

    LYFT  website  

Lyft fares below are the same as you would see via the Lyft app.


Lyft
16-24 $
~5 min away  


Lyft Line
16-17 $
~5 min away  


Lyft Plus
25-36 $
~11 min away  


Lyft Premier
33-45 $
~11 min away  

Q & A

Travel time from 2 Victoria Ct to Newark?

Travel time by taxi is approximately 36 min to get from 2 Victoria Ct to Newark.

Distance between 2 Victoria Ct and Newark?

The road distance between 2 Victoria Ct and Newark is 12.72 miles (20.47 km).

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